(X+a)^n=∑_(k=0)^n?(n|k) X^k A^(n-K)

(x+a)^n=∑_(k=0)^n?〖(n|k) x^k a^(n-k) 〗

by I Only Write Non-Nutritious Novels (我只写没有营养的小说)

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483 Words
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8y ago
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